0.0962*x^2+0.6*x-15=0

Solution for 0.0962*x^2+0.6*x-15=0 equation:

0.0962x^2+0.6x-15=0

a = 0.0962; b = 0.6; c = -15;
Δ = b2-4ac
Δ = 0.62-4·0.0962·(-15)
Δ = 6.132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{6.132}}{2*0.0962}=\frac{-0.6-\sqrt{6.132}}{0.1924}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{6.132}}{2*0.0962}=\frac{-0.6+\sqrt{6.132}}{0.1924}
$